x(3+x)-3(1+2x)=3+x^2

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Solution for x(3+x)-3(1+2x)=3+x^2 equation: 



x(3+x)-3(1+2x)=3+x^2

We move all terms to the left:

x(3+x)-3(1+2x)-(3+x^2)=0

We add all the numbers together, and all the variables

-(3+x^2)+x(x+3)-3(2x+1)=0

We multiply parentheses

-(3+x^2)+x^2+3x-6x-3=0

We get rid of parentheses

-x^2+x^2+3x-6x-3-3=0

We add all the numbers together, and all the variables

-3x-6=0

We move all terms containing x to the left, all other terms to the right

-3x=6

x=6/-3

x=-2

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